修复特定值下计算分流转向比返回结果顺序出现异常bug

app/eva_common.py

@@ -760,6 +760,8 @@ def gen_flow_turn_rate_index(avg_cross_delay_info, roads_dir_dict):
     outroadid_list = [roads_dir_dict[k]['out'] for k in roads_dir_dict.keys()]
     for dir in roads_dir_dict.keys():
         roadid = roads_dir_dict[dir]['in']
+        if 'udr_' in roadid:
+            continue
         l_rate, s_rate, r_rate = 0, 0, 0
         out_l_rate, out_s_rate, out_r_rate = 0, 0, 0
         in_flow_rate, out_flow_rate = 0, 0
@@ -2288,53 +2290,49 @@ def fix_to_100(a, b, c):
     if len(valid_idx) == 2:
         i0, i1 = valid_idx
         v0, v1 = nums[i0], nums[i1]
-        if 100 in (v0, v1) or 0 in (v0, v1):
+        # 只有当两个值恰好是 {0, 100} 时才用特殊处理
+        if {v0, v1} == {0, 100}:
             r1 = random.randint(1, 3)
             r2 = 100 - r1
-            # 原100位放较大值，原0位放较小值
+            if v0 == 100:
-            if v0 == 100 or v1 == 100:
+                nums[i0] = max(r1, r2)
-                idx_100 = i0 if v0 == 100 else i1
+                nums[i1] = min(r1, r2)
-                idx_zro = i1 if v0 == 100 else i0
-                nums[idx_100] = max(r1, r2)
-                nums[idx_zro] = min(r1, r2)
             else:
-                idx_zro = i0 if v0 == 0 else i1
+                nums[i1] = max(r1, r2)
-                idx_nz = i1 if v0 == 0 else i0
+                nums[i0] = min(r1, r2)
-                nums[idx_zro] = min(r1, r2)
+            return _to_int_list(nums, mask)
-                nums[idx_nz] = max(r1, r2)
+        else:
-            return _to_int_list(nums, mask)   # 这里已int，但保险再调一次
+            # 其他情况：正常归一化（包括 100+50, 0+50 等）
-        # 正常值：等比缩放
             s = v0 + v1
+            if s == 0:
+                nums[i0] = 50
+                nums[i1] = 50
+            else:
                 nums[i0] = v0 * 100 / s
                 nums[i1] = v1 * 100 / s
             return _to_int_list(nums, mask)
 
     # ----- 3 个有效 -----
-    if 100 in nums or 0 in nums:
+    # 特殊处理：仅当存在一个 100 且其余两个为 0 时
     if 100 in nums:
-            idx_100 = nums.index(100)
         zeros = [i for i in range(3) if nums[i] == 0]
+        if len(zeros) == 2:
+            # 确认为 [100, 0, 0] 的某种排列
             r1 = random.randint(1, 3)
             r2 = 100 - r1
             nums[zeros[0]] = r1
             nums[zeros[1]] = r2
-            nums[idx_100] = 0          # 先清零，再走下面统一处理
+            # 100 位置保持不变
-        zeros = [i for i in range(3) if nums[i] == 0]
-        if len(zeros) == 1:
-            nums[zeros[0]] = random.randint(1, 3)
-        elif len(zeros) == 2:
-            r1 = random.randint(1, 3)
-            r2 = 100 - r1
-            nums[zeros[0]] = r1
-            nums[zeros[1]] = r2
             return _to_int_list(nums, mask)
 
-    # 正常缩放
+    # 所有其他情况（包括含 0 但无 100，如 [0, 98, 0]）→ 正常归一化
     s = sum(nums)
-    if s == 100:
+    if s == 0:
-        return [int(v) for v in nums]
+        # 全为 0，平均分配（或按需调整）
+        nums = [34, 33, 33]
+    else:
         for i in range(3):
-        nums[i] = max(1, round(nums[i] * 100 / s))
+            nums[i] = nums[i] * 100 / s
     return _to_int_list(nums, mask)